Question 913038

<h4>x-intercept</h4>

To find the x-intercept, plug in {{{y=0}}} and solve for x



{{{x+2y=-1}}} Start with the given equation.



{{{x+2(0)=-1}}} Plug in {{{y=0}}}.



{{{x+0=-1}}} Multiply {{{2}}} and 0 to get 0.



{{{x=-1}}} Simplify.



So the x-intercept is *[Tex \LARGE \left(-1,0\right)].



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<h4>y-intercept</h4>

To find the y-intercept, plug in {{{x=0}}} and solve for y



{{{x+2y=-1}}} Start with the given equation.



{{{0+2y=-1}}} Plug in {{{x=0}}}.



{{{2y=-1}}} Simplify.



{{{y=(-1)/(2)}}} Divide both sides by {{{2}}} to isolate {{{y}}}.



So the y-intercept is *[Tex \LARGE \left(0,-\frac{1}{2}\right)].



Now let's plot the points *[Tex \LARGE \left(-1,0\right)] and *[Tex \LARGE \left(0,-\frac{1}{2}\right)] which are the x and y intercepts respectively.



{{{drawing(500, 500, -10,10,-10,10,
grid(0),
graph(500, 500, -10,10,-10,10,0)
circle(-1,0,0.03),circle(-1,0,0.05),circle(-1,0,0.08),circle(-1,0,0.10),circle(-1,0,0.12),
circle(0,-1/2,0.03),circle(0,-1/2,0.05),circle(0,-1/2,0.08),circle(0,-1/2,0.10),circle(0,-1/2,0.12)
)}}}



Now draw a straight line through the plotted points to graph {{{x+2y=-1}}}.



{{{ drawing(500, 500, -10,10,-10,10,
grid(0),
graph(500, 500, -10,10,-10,10,0,(-1-x)/(2)),
circle(-1,0,0.03),circle(-1,0,0.05),circle(-1,0,0.08),circle(-1,0,0.10),circle(-1,0,0.12),
circle(0,-1/2,0.03),circle(0,-1/2,0.05),circle(0,-1/2,0.08),circle(0,-1/2,0.10),circle(0,-1/2,0.12)
)}}} Graph of {{{x+2y=-1}}}



Let me know if you need more help or if you need me to explain a step in more detail.
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Thanks,


Jim