Question 913014
 a mean of 100 and a standard deviation of 10
P ( x>130) = P(z < 3) = normalcdf(3,100)
P(90 < x < 110) = normalcdf(90,110,100,10)
P(x < 80) = P( z < -2) = normalcdf(-100, -2)
P(120 < x < 130) = normalcdf(120,130,100,10)