Question 912844
{{{a^0 = 1}}}
{{{x^m/x^n=x^(m-n)}}}
{{{( x^m )( x^n ) = x^( m + n )}}}
{{{(a^p)^q = a^(p*q)}}}
{{{(xy)^n = x^n*y^n}}}
(-4m² n³) (2m^1n^1) = -8m^3n^4