Question 912121
Find the exact value of csc q without finding q if tan q = 5/4 and cos q < 0
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you are working with a 3-4-5 right triangle in quadrant III where cos<0, sin<0
hypotenuse of right triangle=&#8730;(5^2+4^2)=&#8730;(25+16)=&#8730;41
tan(q)=sin(q)/cos(q)=5/4
sin(q)=-5/&#8730;41
csc q=1/sin(q)=-&#8730;41/5