Question 77304
HYP=(3X+4) X BEING THE SHORTEST LEG1.
LONGER LEG2=(3X+4)-1
THUS THE HYP^2=(LEG1)^2+(LEG*2)^2
(3X+4)^2=X^2+(3X+4-1)^2
9X^2+24X+16=X^2+(3X+3)^2
9X^2+24X+16=X^2+9X^2+18X+9 WE CAN CANCEL OUT THE 9X^2 TERMS & WE HAVE LEFT
24X-X^2-18X+16-9=0
-X^2+6X+7=0
X^2-6X-7=0
(X-7)(X+1)=0
X-7=0
X=7 ANSWER.
HYP=3*7+4
HYP=21+4
HYP=25 ANSWER.
LONG SIDE=(3*7+3)
LONG SIDE=24 ANSWER.
SHORT SIDE=7 ANSWER.
25^2=24^2+7^2
625=576+49
625=625