Question 10326
Please note:  The previously posted solution to this problem is WRONG!


3x + 3 = 6(x+5)
3x + 3 = 6x + 30


Subtract 3x from each side to get the variables on the right side:
3x - 3x + 3 = 6x - 3x + 30
3=3x + 30


Subtract 30 from each side to get the number terms on the left side:
3 - 30 = 3x + 30 - 30
-27 = 3x


Divide both sides by 3:
x= -9


R^2 at SCC