Question 912339
<u>normally distributed</u> with a mean score of 69 and a standard deviation of 2
*Note: {{{z =blue (x - mu)/blue(sigma/sqrt(n))}}}
z = .2108/(2/sqrt(90)) = 1
P( x > 69.2108)) = 1 - P(z < 1) = 1 - .8413