Question 912398

{{{(1/6)(12x-42)=-(3/4)(4-16x)}}}

{{{ (1/6)6(2x-7)=-(3/4)4(1-4x) }}}

{{{(1/cross(6))cross(6)(2x-7)=-(3/cross(4))cross(4)(1-4x)}}}

{{{(2x-7)=-3(1-4x)}}}

{{{2x-7=-3+12x}}}

{{{3-7=12x-2x}}}

{{{-4=10x}}}

{{{-4/10=x}}}

{{{-2/5=x}}}