Question 912354
Find the dimensions of the rectangle that has a length of 3 meters more than its width and a perimeter equal in value to its area?
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let x=width
x+3=length
..
2(width+length)=2(x+x+3=4x+6=perimeter
width*length=x(x+3)=x^2+3x=area
4x+6=x^2+3x
x^2-x-6=0
(x-3)(x+2)=0
x=3
x+3=6
dimensions of the rectangle: 
width=3
length=6