Question 912234
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The probability that the first letter selected is an "I" is *[tex \Large \frac{4}{11}].  The probability that the second letter is an "I" given that the first letter was an "I" is *[tex \Large \frac{3}{10}] (One less letter and one less "I").  The probability of both, being independent events, is *[tex \Large \left(\frac{4}{11}\right)\left(\frac{3}{10}\right)\ =\ \frac{12}{110}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \