Question 912258
Find the range of the function and write it using interval notation:
f(x)=10-(x-2)^2
solve for x in terms of y
y=10-(x-2)^2
(x-2)^2=10-y
x-2=±√(10-y)
x=2±√(10-y)
(10-y)≥0 (radican≥0)
-y≥-10
y≤10
range:(-∞,10]