Question 912136
{{{(x+1)/(x-1)=(-7x)/(x+3)+(8)/(x-1)(x+3)}}}
Use (x-1)*(x+3) as the commmon denominator
{{{(x+1)*(x+3)/((x-1)*(x+3))=(-7x)*(x-1)/((x-1)*(x+3)) + 8/(x-1)(x+3)}}}
Since the DEN's are equal:
{{{(x+1)*(x+3) = (-7x)*(x-1) + 8}}}
{{{x^2 + 4x + 3 = -7x^2 + 7x + 8}}}
{{{8x^2 - 3x - 5 = 0}}}
(x - 1)*(8x + 5) = 0
x = 1  --- reject, makes the DEN zero
x = -5/8