Question 912075


The average of {{{6}}} numbers is {{{4}}}. If one of the numbers is {{{2}}}, what is the average of the other {{{5}}} numbers? 

{{{(x+y+a+b+c+d)/6=4}}} ...if {{{x=2}}}, then

{{{(2+y+a+b+c+d)/6=4}}}

{{{(2/6)+(y+a+b+c+d)/6=4}}}

{{{(1/3)+(y+a+b+c+d)/6=4}}}

{{{(y+a+b+c+d)/6=4-1/3}}}

{{{(y+a+b+c+d)/6=12/3-1/3}}}

{{{(y+a+b+c+d)/6=11/3}}}

{{{(y+a+b+c+d)/6=3.666666666666667}}}

{{{(y+a+b+c+d)/6=3.7}}}