Question 77272
(6x-2)^.5 - (4x-3)^.5 = 1
{{{sqrt(6x - 2) - sqrt(4x - 3) = 1}}}
{{{sqrt(6x - 2) = 1 + sqrt(4x - 3)}}}
{{{(sqrt(6x - 2))^2 = (1 + sqrt(4x - 3))^2}}}
{{{6x - 2 = 1 + 2*sqrt(4x - 3) + 4x - 3}}}
{{{6x - 4x - 2 + 3 - 1 = 1 - 1 + 2*sqrt(4x - 3) + 4x - 4x - 3 + 3}}}
{{{2x = 2*sqrt(4x - 3)}}}
{{{2x/2 = 2*sqrt(4x - 3)/2}}}
{{{x = sqrt(4x - 3)}}}
{{{(x)^2 = (sqrt(4x - 3))^2}}}
{{{x^2 = 4x - 3}}}
{{{x^2 - 4x + 3 = 0}}}
{{{(x - 3)(x - 1) = 0}}}
x = 3 and x = 1
Sum Solutions: 3 + 1 = 4