Question 911922

let' number be {{{x}}} 


One third of a number ({{{(1/3)x}}}) added to itself ({{{x}}})

{{{(1/3)x+x}}} 

 equals =


{{{3}}} times the difference of the number ({{{x}}}) and {{{7}}}

{{{ 3(x-7) }}}

so, put it together:

{{{(1/3)x+x=3(x-7)}}} ....solve for {{{x}}}

{{{(1/3)x+x=3(x-7)}}} ...both side multiply by {{{3}}}

{{{3(1/3)x+3x=3*3(x-7)}}}

{{{x+3x=9(x-7)}}}

{{{4x=9x-63}}}

{{{63=9x-4x}}}

{{{63=5x}}}

{{{63/5=x}}}

{{{12.6=x}}}