Question 911761
10(5-10^3x-5)=9

x=
<pre>
{{{10(5 - 10^(3x - 5)) = 9}}}
{{{5 - 10^(3x - 5) = 9/10}}}
{{{5 - 9/10 = 10^(3x - 5)}}} 
{{{4&1/10 = 10^(3x - 5)}}}
{{{10^(3x - 5) = 41/10}}}
{{{log (41/10) = 3x - 5}}}
log 41 – log 10 = 3x – 5
log 41 – 1 = 3x – 5
log 41 = 3x – 5 + 1
log 41 = 3x – 4
{{{log (10, 41/10) = 3x - 4}}} ------- Applying change of base 
1.612784 = 3x – 4
1.612784 + 4 = 3x
5.612784 = 3x
{{{5.612784/3 = x}}}, or {{{highlight_green(highlight_green(x = 1.870928))}}}
You can do the check!! 
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