Question 911760

I'm having a little trouble factoring trinomials. Ex. u^3= 14u^2 + 32u. I do: 0= -u^3 + 14u^2 + 32u. Then, according to my algebra book, I factor, or seem to, it to: 0= u(u^2 + 14u + 32). Do I factor out the part in the parentheses? I can't seem to- paired factors of 32 that add up to 14... Or do I have it wrong? I just want to know the next step(s).
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You have it all wrong!!
If the equation you described is: {{{u^3 = 14u^2 + 32u}}}, then we get: {{{u^3 - 14u^2 - 32u = 0}}}
{{{u(u^2 - 14u - 32) = u(0)}}}
{{{u^2 - 14u - 32 = 0}}}
(u - 16)(u + 2) = 0
{{{highlight_green(u = 16)}}}        OR        {{{highlight_green(u = - 2)}}}

You were correct, at first when you obtained: {{{0 = - u^3 + 14u^2 + 32u}}}. From here on though, you
should've gotten: {{{- u(0) = - u(u^2 - 14u - 32)}}}. This then results in: {{{u^2 - 14u - 32 = 0}}}