Question 911545
0 C=32 F
100 C=212 F
So then,
{{{F=aC+b}}}
Plug in the values,
{{{32=a(0)+b}}}
{{{b=32}}}
.
.
{{{212=a(100)+32}}}
{{{180=100a}}}
{{{a=1.8}}}
.
.

.
So then,
{{{highlight(F=1.8C+32)}}}