Question 77203
A=1/2h(B+b) [multiply each side by "2" in order to cancell "1/2"]
(2)A=(2)(1/2)h(B+b)
2A=h(B+b)
(1/h)2A=(1/h)h(B+b) [multiply each side by "1/h" in order to cancell the h-term
(2A)/h -B=B-B+b
(2A)/h -B=b [subtract the B-term from both sides to cancell the B-term]
.
check by plugging b=(2A/h)-B back into the original equation and solve:
A=1/2h(B+[(2A/h)-B)[cancel wherever possible]
A=A [checks out]