Question 911618
Need to Know:  the vertex form of a Parabola opening up(a>0) or down(a<0): 
{{{y=a(x-highlight(h))^2 +k}}} where(h,k) is the vertex  and  x = h  is the Line of Symmetry

Y= {{{highlight_green(2)}}}(x-2)^2-2  
Upward a = 2 > 0
V(2,-2), axis of symmetry:  x = 2
{{{drawing(300,300,   -6, 8, -6, 6, grid(1), blue(line(2,8,2,-6)) ,

graph( 300, 300, -6, 8, -6, 6,0,2(x-2)^2 - 2 ))}}}