Question 911615
Need to Know:  the vertex form of a Parabola opening up(a>0) or down(a<0): 
{{{y=a(x-h)^2 +k}}} where(h,k) is the vertex  and  x = h  is the Line of Symmetry

Y= {{{highlight_green(2)}}}(x+1)^2-4  
Upward a = 2 > 0
V(-1,-4), axis of symmetry:  x = -1
{{{drawing(300,300,   -6, 8, -6, 6, grid(1), blue(line(-1,8,-1,-6)) ,

graph( 300, 300, -6, 8, -6, 6,0, 2(x+1)^2-4) )}}}