Question 911613
Need to Know:  the vertex form of a Parabola opening up(a>0) or down(a<0): 
{{{y=a(x-h)^2 +k}}} where(h,k) is the vertex  and  x = h  is the Line of Symmetry

y = 1(x-5)^2 + 0
{{{drawing(300,300,   -6, 8, -6, 6, grid(1), 

graph( 300, 300, -6, 8, -6, 6,0, (x-5)^2) )}}}