Question 911570
y = x^2 + x + 1
Take Integral
f(x) = x^3/3 + x^2/2 + x
A = f(2) - f(1) =  20/3 - 11/6  = 4.833
x = (1/A){{{int(x( x^2 + x + 1), dx, 1, 2) = (1/4.833)int(( x^3 + x^2 + x), dx, 1, 2  ) = 7.5833/4.8333 = 1.569}}}
Evaluating: x^4/4 + x^3/3 + x^2/2] from 1 to 2 = 7.5833 
y = (1/A){{{int(( x^2 + x + 1)^2/2, dx, 1, 2)}}}