Question 911407
Let {{{ d }}} = the distance in miles traveled
Let {{{ t }}} = the time in hours for Tyler to travel {{{ d }}} miles
{{{ t + 2/3 }}} = time in hours for Ricky to travel {{{ d }}} miles
( Note that {{{ 2/3 }}} hrs  = {{{ 40 }}} min )
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Tyler's equation:
{{{ d = 54t }}}
Ricky's equation:
{{{ d = 30*( t + 2/3 ) }}}
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By substitution:
{{{ 54t = 30*( t + 2/3 ) }}}
{{{ 54t = 30t + 20 }}}
{{{ 24t = 20 }}}
{{{ t = 5/6 }}}
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{{{ d = 54t }}}
{{{ d = 54*(5/6) }}}
{{{ d = 45 }}}
The distance traveled is 45 mi
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check:
{{{ d = 30*( t + 2/3 ) }}}
{{{ 45 = 30*( 5/6+ 2/3 ) }}}
{{{ 45 = 30*( 5/6 + 4/6 ) }}}
{{{ 45 = 30*( 9/6 ) }}}
{{{ 45 = 45 }}}
OK