Question 911178
We don't know the total invested.
We know the difference in the two accounts.
We know that the interest for the two accounts is $2200
0.06*x+0.1*y=2200
We know that the account at 6% has $2000 more.
x=2000+y
We substitute for x
0.06*(2000+y)+0.1*y=2200
We multiply out
120+0.06y+0.1*y=2200
We combine like terms.
0.16*y=2080
Isolate y
y=$13000 at 10%
x=2000+y
Calculate x
x=$15000 at 6%
Now,we know the total invested is: 28000
Total invested $15000+$13000=$28000
We check
0.06*15000+0.1*13000=2200
900+1300=2200
2200=2200
Since this statement is TRUE and neither x nor y is negative all is well.
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