Question 911008
{{{f(x)=-(2/3)(x+2)^2-1}}}
(parentheses around 2/3 to make rendering show the actual function you want).


The function is in standard form.  The x-intercepts happen for {{{f(x)=0}}}, easily solved, since you already have f in standard form.  Do this!


The y-intercept occurs for x=0; so just evaluate {{{f(0)}}}.



{{{graph(300,300,-5,5,-5,5,-(2/3)(x+2)^2-1)}}}


You should be able to understand the situation of the x-intercepts from the algebraic solving process of finding those values.