Question 77142
Differentiate the following function with respect to t. 
y = 5/t^2 + 6t^3 - sqrt t 

Rewrite as:
y = 5t^-2 + 6t^3 - t^(1/2)

y' = -10t^-3 + 18t^2 - (1/2)t^(-1/2)

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Cheers,
Stan H.