Question 77064
*[invoke factoring_quadratics 1, -1, -56]

{{{(x+7)(x-8)=0}}}

Now set each factor equal to zero 

{{{x+7=0}}}
{{{x=-7}}}

{{{x-8=0}}}
{{{x=8}}}

So our answer is:

{{{x=-7}}} or {{{x=8}}}

Since a negative answer doesn't work, the answer is {{{x=8}}}