Question 910595
The bases are the same (both are y). When you divide expressions like this, you subtract the exponents


So,


{{{(y^4)/(y^(11)) = y^(4-11) = y^(-7)}}}


Most books want the exponent to be positive, so flip the fraction (y = y/1) to get 1/y with a positive exponent of 7.


So {{{y^(-7) = 1/(y^7)}}}


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Therefore, {{{(y^4)/(y^(11)) = 1/(y^7)}}}