Question 910399
We need a total of 35 gal at 12%
We want to know how many gal at 6% to mix with 20%
a+b=35,
0.06*a+0.2*b=0.12*35
a=35-b
0.06*(35-b)+0.2*b=4.2
2.1-0.06b+0.2*b=4.2
0.14*b=2.1
b=15
a=35-b
a=20 gal at 6%
b=15 gal at 20%
check
0.06*20+0.2*15=0.12*35
1.2+3=4.2
4.2=4.2
ok
codemx1