Question 910256
10 liter solution that is 30% alcohol is going to be diluted to 20% alcohol by adding water
 how much is water is needed
:
let w = amt of water required to accomplish this
Use the decimal equiv of percent
.30(10) = .20(w+10)
3 = .2w + 2
3 - 2 = .2w
w = 1/.2
w = 5 liters of water