Question 910329
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{x}\ +\ \frac{1}{x\ +\ 2}\ =\ \frac{28}{195}]


Solve for *[tex \Large x] and then calculate *[tex \Large x\ +\ 2]


Hint:  Combine the two fractions in the LHS using the lowest common denominator of *[tex \Large x^2\ +\ 2x].  Then equate the two numerators and solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \