Question 910307
Vertical asymptotes occur when the denominator equals zero.
{{{x-7=0}}}
{{{x=7}}}
Horizontal asymptotes occur in the limit as x goes to infinity.
{{{lim(x->infinity,((x+28))/((x-7)))=lim(x->infinity,((1+28/x))/((1-7/x)))=((1+0))/((1-0))=1}}}
So a horizontal asymptote occurs at {{{y=1}}}
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{{{drawing(300,300,-40,60,-10,10,blue(line(-70,1,70,1)),green(line(7,-60,7,60)),graph(300,300,-40,60,-10,10,(x+28)/(x-7)))}}}