Question 910301


the length {{{L}}} of a rectangle is seven more than three times the width {{{W}}}

{{{L=3W+7ft}}}

 and the perimeter is {{{P=110ft}}}

since {{{P=2(L+W)}}}, we have

{{{110ft=2(L+W)}}} 

{{{110ft/2=L+W}}} 

{{{55ft=L+W}}} ...substitute {{{L=3W+7ft}}}

{{{55ft=3W+7ft+W}}} ....solve for {{{W}}}

{{{55ft-7ft=4W}}}

{{{48ft=4W}}}

{{{48ft/4=W}}}

{{{highlight(W=12ft)}}}

now find {{{L}}}

{{{L=3W+7ft}}}

{{{L=3*12ft+7ft}}}

{{{L=36ft+7ft}}}

{{{highlight(L=43ft)}}}