Question 910203
{{{log((4x-7))+log((x^2+4))=0}}}, the base is "a".


{{{log(((4x-7)(x^2+4)))=0}}}


{{{a^0=(4x-7)(x^2+4)}}}


{{{1=(4x-7)(x^2+4)}}}
You would want to simplify this and use Rational Roots Theorem if you want the SOLUTIONS for the equation.  Could a value for x for which {{{4x-7<0}}} be acceptable in this equation?  I believe not.  You usually find logarithms of POSITIVE numbers of 0.