Question 909965
m = 2.5, sd = .4
1) normalcdf(2.0,2.6,2.5,.4)
2) normalcdf(-10,2.7,2.5,.4)
3) .4invNorm(.93) + 2.5 = X

4 t1 = (.1/(.4/sqrt(49)) and t2 = (.2/(.4/sqrt(49))
 P(t2< value) - P(t1< value)
Use df = 48
tcdf(-100,3.5 , 48) - tcdf(-100,1.75 , 48)