Question 909838
From your picture,
{{{((a^5b^(-4))^(n-1)/(a^(-3)b)^(2-n))*(a^2/b^(-1))^(2n+1)=a^(5(n-1))b^(-4(n-1))*a^(3(2-n))b^(-(2-n))*a^(2(2n+1))*b^(2n+1)}}}
{{{((a^5b^(-4))^(n-1)/(a^(-3)b)^(2-n))*(a^2/b^(-1))^(2n+1)=a^(5n-5)b^(-4n+4)*a^(6-3n)b^(n-2)*a^(4n+2)*b^(2n+1)}}}
{{{((a^5b^(-4))^(n-1)/(a^(-3)b)^(2-n))*(a^2/b^(-1))^(2n+1)=a^(5n-5+6-3n+4n+2)*b^(-4n+4+n-2+2n+1)}}}
{{{((a^5b^(-4))^(n-1)/(a^(-3)b)^(2-n))*(a^2/b^(-1))^(2n+1)=a^(6n+3)*b^(-n+3)}}}