Question 909847
3log(-3) = log (-27)
*[tex \large\ \ nlog_bx = log_b(x^n) ] ****
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]