<PRE><B>Question 909782</B>
We know that the interest for the two accounts is $426
0.045*x+0.149*y=426
We know that the account at 4.5% has 3 times the amount at 14.9%
We substitute for x
0.045*(3*y)+0.149*y=426
We multiply out
(0.135+0.149)*y=426
We combine like terms.
0.284*y=426
Isolate y
y= 1500.00
y=$ 1500.00 at 14.9%
Calculate x
x=3*y
x=$ 4500.00 at 4.5%
Your total for x  is $ 4500.00
Your total for y is $ 1500.00
Your total for x and y is $ 6000.00
Total invested $ 4500.00 + $ 1500.00=$ 6000.00
We check
0.045* 4500.00+0.149* 1500.00=426
  202.50+  223.50=426
426.0=426
Since this statement is TRUE and neither x nor y  is negative then all is well.
</PRE>