Question 909603
I am to graph the quadratic function, identify the axis of symmetry, and the coordinates of the vertex
 For y = -x^2+5x-3
-x^2+5x = y+3
-(x^2-5x) = y+3
-(x^2 - 5x + (5/2)^2) = y+3 -(5/2)^2
-(x-(5/2))^2 = y+(12/4)-(25/4)
-(x-(5/2))^2 = y-(13/4)
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Axis of symmetry:: x = 5/2
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Vertex:: When x = 5/2, y = 13/4
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Cheers,
Stan H.
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