Question 909603
The axis of symmetry should be


{{{x = -b/(2a)}}}


{{{x = -5/(2(-1))}}}


{{{x = 5/2}}} Notice how the two negatives cancel


This x value will be plugged back into {{{y=-x^2+5x-3 }}} to find the y coordinate of the vertex.


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You have the correct y-intercept, but the x-intercept is incorrect. 


You need to solve {{{-x^2+5x-3 =0}}} for x.


You would use the quadratic formula to do this.