Question 909586

When {{{1}}} is added to the difference between six times a number {{{x}}} and {{{7}}},we have 

{{{(6x-7)+1}}}...first part
 
the result is greater than {{{11}}} added to {{{5}}} times the number {{{x}}}

{{{5x+11}}} ...second part

together:

{{{(6x-7)+1>5x+11}}} ...solve for {{{x}}}

{{{6x-7+1>5x+11}}}

{{{6x-6>5x+11}}}

{{{6x-5x>6+11}}}

{{{x>17}}}

so, the solutions are all numbers greater than_{{{17}}}__