Question 909501
Either {{{x+1>=0}}}  OR {{{x+1<0}}}.
Solve for each case.


That will mean, either {{{abs(x+1)=x+1}}} or {{{abs(x+1)=-(x+1)}}}.


(I give this unfinished and you can use this to continue and finish.)


The nonzero case:  {{{x+1=x+1}}} will be true for all values as long as {{{x+1>0}}},
{{{x>-1}}} ------so this is part of the solution.


The zero case:  {{{-x-1=x+1}}}
{{{-x-x=1+1}}}
{{{-2x=2}}}
{{{x=-1}}}-------another part of the solution.


Putting these two together will be all of the solution set, since they both work.
{{{highlight(x>=-1)}}}.