Question 909514
We don't know the total invested.
We know the difference in the two accounts.
We know that the interest for the two accounts is $260
0.12*x+0.1*y=260
We know that the account at 12% has $700 more.
x=700+y
We substitute for x
0.12*(700+y)+0.1*y=260
We multiply out
84+0.12y+0.1*y=260
We combine like terms.
0.22*y=176
Isolate y
y=$800 at 10%
x=700+y
Calculate x
x=$1500 at 12%
Now,we know the total invested is: 2300
Total invested $1500+$800=$2300
We check
0.12*1500+0.1*800=260
180+80=260
260=260
Since this statement is TRUE and neither x nor y is negative all is well.