Question 909339


{{{y = a(b)^x }}}
 when {{{0 < b < 1}}} => {{{decrease }}}
 when {{{b > 1}}} => {{{increase}}} 

in your case

{{{y=11(1/6)^x}}} => {{{b=1/6}}}
and, since  {{{ 1/6 < 1}}} => {{{decrease }}}