Question 909321

The length of a rectangle, {{{L}}}, is equal to {{{3}}} more than 
{{{3}}} times the width, {{{W}}}. 

{{{L=3W+3ft}}} ....eq.1
 
The perimeter, {{{P}}}, is {{{54ft}}}.

{{{P=2(L+W)}}} ..substitute {{{L=3W+3}}} and {{{P=54ft}}}

{{{54ft=2(3W+3ft+W)}}} ...solve for {{{W}}}

{{{54ft=2(4W+3ft)}}}

{{{54ft/2=(4W+3ft)}}}

{{{27ft-3ft=4W}}}

{{{24ft=4W}}}

{{{24ft/4=W}}}

{{{highlight(W=6ft)}}}

now find the length


{{{L=3W+3ft}}} ....eq.1

{{{L=3*6ft+3ft}}} 

{{{L=18ft+3ft}}}

 {{{highlight(L=21ft)}}}