Question 909166
Ten years at two compoundings per year is 20 compounding periods of time.  The initial investment quantity is unknown and can be solved.  Call this a.


{{{290000=a*(1.085)^20}}}, not using a Natural Log model (although it could be used instead).


The rate is used as 1+0.085, as a decimal number.


{{{log(10,290000)=log(10,a)+log(10,1.085^20)}}}
{{{log(10,290000)=log(10,a)+20*log(10,1.085)}}}
{{{log(10,a)=log(10,290000)-20*log(10,1.85)}}}
{{{log(10,a)=5.4624+20*0.0354297}}}
{{{log(10,a)=5.4624-0.7086}}}
{{{log(10,a)=4.7538}}}
{{{highlight(a=56728.33)}}}-----The amount to invest.


Each person of the village, of 958 people, would pay {{{a/958}}} dollars, or
{{{a=56728.33/958=highlight(59.22)}}} dollars each.


My calculations may not have used the accuracy specified in the problem description.  Precision might be off a little bit.  software calculator was used; not a table of logarithms.


Try checking:
{{{56728*1.085^20=289996}}},  not too far from 290000.