Question 909041
....... you mean, "Solve for b." 


LCD is b^2-1, the difference of squares as found in the denominators on the left member.


{{{(1/(b+1)+1/(b-1))(b-1)(b+1)=(2/(b^2-1))(b-1)(b+1)}}}


{{{b-1+b+1=2}}}


{{{2b=2}}}


{{{highlight(b=1)}}}