Question 909105
"Find the three consecutive integers such that 2 times the sum of the first two is 1 less than 3 times the third"

x = 1st integer
x+1= 2nd integer
x+2 = 3rd integer

2 times the sum of the first two is 1 less than 3 times the third:
2(x+x+1)= 3(x+2)-1 
2x+2x+2 = 3x+6-1
4x+2 = 3x+5
x=3
first integer: 3
second integer: 4
third integer: 5