Question 909103

{{{f(x)=(3x-1)^3}}} ....if you need to expand:

{{{f(x)= (3x-1)(3x-1)(3x-1)}}}

{{{f(x)= (9x^2-3x-3x+1)(3x-1)}}}

{{{f(x)= (9x^2-6x+1)(3x-1)}}}

{{{f(x)= 9x^3-9x^2-18x^2+6x+3x-1}}}

{{{f(x)= 9x^3-27x^2+9x-1}}}


{{{f(x)=(3x-1)^3}}} ....if you need to find solutions

{{{f(x)= (3x-1)(3x-1)(3x-1)  }}}

{{{f(x)=0}}} if {{{(3x-1)(3x-1)(3x-1)=0  }}} or {{{3x-1=0  }}} since all factors are same, means three identical roots

{{{3x-1=0  }}} => {{{3x=1  }}} => {{{x=1/3  }}} 

 {{{ graph( 600, 600, -5, 5, -10, 10, (3x-1)^3) }}}